What Is A Regular Polygon’S Maximum External Angle?

The exterior angles of a polygon are formed by extending one side at the vertex, and the sum of these angles is 360°. A regular hexagon has a maximum exterior angle of 60°, while its interior angle is 120°. The sum of the measures of the exterior angles in a polygon is calculated using the formula 360°/Number of sides of the polygon.

To find the measure of a single exterior angle, divide the measure of the sum of the exterior angles with the total number of sides. Exterior angles are supplementary to the interior angles, meaning that the sum of an exterior angle and its interior angles can be used to solve problems.

The maximum exterior angle measurement for a regular polygon is (180 – 60)o = 120, with 120° being the highest exterior angle for an equilateral triangle. The minimum interior angle of a regular polygon is 60°, so the maximum possible exterior angle is 180o60o=120o.

The maximum possible exterior angle of a regular polygon is 120°, as the polygon with the fewest sides has the highest exterior angle. The measure of each exterior angle of a regular polygon of 9 sides and 15 sides is 40° and 24°, respectively. This knowledge can be used to solve problems and prepare for exams such as Edexcel, AQA, and OCR GCSE.

What is the maximum exterior angle possible for a regular polygon?

The maximum exterior angle that can be formed by a regular polygon is 120°, as the exterior angle and interior angle are in a linear pair. The minimum interior angle for a regular polygon is 60°, as the sum of all angles of a triangle is equal to 180°. This is due to the fact that the exterior angle and interior angle form a linear pair.

Is it possible to have a regular polygon with an exterior angle of 100?

The assertion that “it is not possible to have a regular polygon whose exterior angle is 100°” is erroneous. The number of sides is designated as n, and each exterior angle is equal to 100°. It thus follows that a regular polygon cannot have an exterior angle of 100°.

What is the largest exterior angle of a regular polygon?

The highest exterior angle of a regular polygon (equilateral triangle) is 120°, as it is the polygon with the least number of sides. This can be demonstrated by calculating the ratio of 360° to the number of sides and establishing that the result is an integer. This represents the maximum exterior angle for any regular polygon.

Can we have a regular polygon whose each exterior angle is 120?

The exterior angles of a polygon are in arithmetic progression, with the sum of the angles equaling 360°. Consequently, each angle is 360°/n, where n is the number of sides in the polygon. This yields a triangle with exterior angles of 120°. The sum of any exterior angle and its corresponding interior angle is always 180 degrees, resulting in a straight angle. The interior angles of the polygon have a measure of 60 degrees, which indicates that the polygon has a regular shape.

Is it possible to have a regular polygon with an exterior angle of 24?

The number of sides of a regular polygon is determined by the sum of all exterior angles, which is 360°. The number of sides is calculated by dividing the sum of the exterior angles by each exterior angle.

Can a regular polygon have 13.5 as its exterior angle?

A regular polygon cannot have 13. 5 as its exterior angle due to its symmetry. The exterior angles of a regular polygon are always equal, and the measure of each exterior angle can be found by dividing 360 by the number of sides. For example, in a polygon with 10 sides, each exterior angle measures 360/10 = 36 degrees. Since 13. 5 is not a whole number, it cannot be the measure of an exterior angle in a regular polygon.

Is it possible to have a polygon with exterior angle of 22?

It is not possible for a regular polygon to have an exterior angle of 22° due to the non-zero number of sides. The number of sides can be calculated by dividing the sum of the exterior angles by each angle.

Which polygon has an exterior angle of 120°?

A regular polygon with 120 exterior angles is congruent with a triangle. The interior angles of this polygon are 180 degrees, as they form a straight line. The interior angles have a measure of 60 degrees, as the exterior angles total 360°, resulting in a total of 120 degrees.

Why is it not possible to have a polygon with an exterior angle of 23?

The regular icositrigon is not constructible with a compass and straightedge or angle trisection, as 23 is neither a Fermat nor Pierpont prime. It is also the smallest regular polygon not constructible even with neusis. A. Baragar demonstrated that constructing a regular 23-gon using only a compass and twice-notched straightedge is not possible. He demonstrated that every point constructible with this method lies in a tower of fields over which the degree of extension at each step is 2, 3, 5, or 6. If in is constructible using a compass and twice-notched straightedge, it belongs to a field in a tower of fields with the index at each step being 2, 3, 5, or 6.

Is it possible to have 50 degree as exterior angle of a regular polygon?

The formula for calculating the exterior angle of a regular polygon is (360/n)°, where n is the number of sides in the polygon. This formula is not exactly divisible by 50, as the result is not an integer.

Is it possible to have a regular polygon with an exterior angle of 60?

It is not possible for the figure to be an equilateral triangle with three equal sides if each interior angle of the regular polygon is 60 degrees, or a hexagon with six equal sides if each exterior angle is 60 degrees.